Given Equation:-
[tex]\red{➤}\:[/tex][tex]\sf \dfrac{6+8x}{2} = 5x[/tex]
[tex]\\[/tex]
To Find:-
[tex]\orange{☛}\:[/tex][tex]\sf Value \:of \: x [/tex]
[tex]\\[/tex]
Solution:-
[tex]\begin{gathered}\\\quad\longrightarrow\quad\sf \frac{6+8x}{2} = 5x \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\quad\longrightarrow\quad\sf 6+8x= 5x×2 \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\quad\longrightarrow\quad\sf 6+8x= 10x \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\quad\longrightarrow\quad\sf 8x-10x= -6 \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\quad\longrightarrow\quad\sf -2x = -6 \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\quad\longrightarrow\quad\sf x = \frac{-6}{-2} \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\quad\longrightarrow\quad\boxed{\sf {x = 3}} \\\end{gathered} [/tex]
Remember-
On Transfering the terms to other side of equation-
+ changes to -
- changes to +
× changes to ÷
÷ changes to ×
