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Sagot :

Given Equation:-

[tex]\red{➤}\:[/tex][tex]\sf \dfrac{6+8x}{2} = 5x[/tex]

[tex]\\[/tex]

To Find:-

[tex]\orange{☛}\:[/tex][tex]\sf Value \:of \: x [/tex]

[tex]\\[/tex]

Solution:-

[tex]\begin{gathered}\\\quad\longrightarrow\quad\sf \frac{6+8x}{2} = 5x \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\quad\longrightarrow\quad\sf 6+8x= 5x×2 \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\quad\longrightarrow\quad\sf 6+8x= 10x \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\quad\longrightarrow\quad\sf 8x-10x= -6 \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\quad\longrightarrow\quad\sf -2x = -6 \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\quad\longrightarrow\quad\sf x = \frac{-6}{-2} \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\quad\longrightarrow\quad\boxed{\sf {x = 3}} \\\end{gathered} [/tex]

Remember-

On Transfering the terms to other side of equation-

+ changes to -

- changes to +

× changes to ÷

÷ changes to ×

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