Answered

Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Experience the convenience of getting reliable answers to your questions from a vast network of knowledgeable experts. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

Solve these 2 questions

1. Solve for X. X^3 + 10 x 23 = 355

2. If bob gains 5 apples a day and Billy gains twice as many apples as bob but loses 3 on the 3 day of every month than how many apples would than have gained in total over the course of 10 decades

Sagot :

camandace02
1. x^3 + 10 x 23 = 355
10 x 23 = 230
355 - 230 = 125
cube root of 125 is 5
So,
x = 5

2.
Bob = 5 per day for 100 years
Billy = 10 per day for 100 years minus 3 every month

Bob = 5 x 365 = 1,825 per year
Billy = 5 x 2 x 365 = 10 x 365 = 3,650 per year without reduction of 3 apples per month
12 months per year x 3 apples = 36 so 3,650 - 36 = 3,614 apples per year so billy = 3,614 apples per year

Bob = 1,825 x 100 = 182,500 apples after 10 decades
Billy = 3,614 x 100 = 361,400 apples after 10 decades
So,
Bob = 182,500 apples
Billy = 361,400 apples
Not including leap years

Including leap year would =
Bob = about 182,625 apples
Billy = about 367,650 apples

Because leap year is every 4 years and 100 years / 4 years = 25 years so
Bob = 1,830 x 25 + 1,825 x 75 = 182,625 apples
Billy = 3,624 x 25 + 3,614 x 75 = 367,650 apples

Sorry if it looks complicated
Hope this helps ;)


Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.