Answered

Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Our platform provides a seamless experience for finding reliable answers from a knowledgeable network of professionals. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

calculate the moles and Molecules presents in ammonia present in 5.6dm3
of its volume STP?

​

Sagot :

rspill6

Answer: 0.25 moles NH3

              1.51x10^23 molecules NH3

Explanation:

5.6dm3 (cubic decimeters)

1 dm^3 = 1 liter

We have 5.6L of ammonia (NH3 gas) at STP.  All gases at STP occupy 22.4 liters/mole.  Use this information as a conversion factor:

(22.4 L NH3)/(mole NH3)

Therefore:

(5.6L NH3)/(22.4 L NH3)/(mole NH3) = 0.25 moles NH3

Use Avogadro's number to convert moles to particles/molecules

(0.25 moles NH3)*(6.02x10^23 molecules/mole) = 1.51x10^23 molecules NH3

Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.