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calculate the moles and Molecules presents in ammonia present in 5.6dm3
of its volume STP?

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Sagot :

rspill6

Answer: 0.25 moles NH3

              1.51x10^23 molecules NH3

Explanation:

5.6dm3 (cubic decimeters)

1 dm^3 = 1 liter

We have 5.6L of ammonia (NH3 gas) at STP.  All gases at STP occupy 22.4 liters/mole.  Use this information as a conversion factor:

(22.4 L NH3)/(mole NH3)

Therefore:

(5.6L NH3)/(22.4 L NH3)/(mole NH3) = 0.25 moles NH3

Use Avogadro's number to convert moles to particles/molecules

(0.25 moles NH3)*(6.02x10^23 molecules/mole) = 1.51x10^23 molecules NH3

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