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Write a quadratic equation in standard form with integral coefficients given
x = 4 is a solution with multiplicity of 2.


Sagot :

Answer:

y=(x-4)^2=x^2-8x+16

Step-by-step explanation:

Since we know that x=4 is a solution with multiplicity 2. Therefore x=4 will occur as a factor twice in the quadratic equation.

So

y=(x-4)^2

[tex]y=(x-4)^2=x^2-8x+16[/tex]