The answers to both are attached. Also hello to person in same class & same hw, physics 2 been a bummer but not too bad--just annoying in general.
Ampere's law allows us to find the results for the magnetic field at two distances from a system made up of two conductors:
a) Magnetic field inside the system is: [tex]b= \frac{\mu_o }{2\pi } \ \frac{I}{r}[/tex]
b) Magnetic field for the outside of the system is; b = 0
Ampere's law states that the dot product of the magnetic field times a closed path is proportional to the current within the path.
∫ B. ds = μ₀ I
Where bold indicates vectors, B is the magnetic field, S the closed path, muo the vacuum permittivity and I the current
a) Ask the magnetic field inside the two conductors.
Let's fix a circular path within the system, see attached, in this case the current that stops inside the path is I.
The circle length is
s = 2π r
B 2π r = μ₀ I
[tex]B = \frac{\mu_o}{2\pi } \ \frac{I}{r}[/tex]
b) Ask the magnetic field on the outside of the two wires.
Let's use a circular path in the outer part of the system, see attached, in this case with indicate that the current is the two cables is of equal magnitude and in the opposite direction the net current is zero, consequently by Ampere's law
B=0
In conclusion using Ampere's law we can find the magnetic field for the distances of a system formed by two conductors are:
a) Magnetic field inside the systemis: [tex]B = \frac{\mu_o}{2\pi } \ \frac{I}{r}[/tex]
b) Magnetic field outside of the system is; B = 0
Learn more about Ampere's law here: brainly.com/question/17070619
