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solve 0+x^2-10x+30 by completing the square

Sagot :

Answer:

See answer below

Step-by-step explanation:

x² - 10x + 30 = 0

x² - 10x = -30

x² - 10x + 25 = -30 +25     1/2 of the x term and square that number and add to

                                          both side.

x² -10x + 25 = -5

(x - 5)(x - 5) = -5

[tex]\sqrt{(x-5)(x-5)^2}[/tex] = [tex]\sqrt{-5}[/tex]    

If you are in Algebra II , then the answer is not a real answer it will be

(x - 5)² = ±5i

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