Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Get the answers you need quickly and accurately from a dedicated community of experts on our Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

The first three terms of a sequence are given. Round to the nearest thousandth (if necessary).
6, 8, 32/3...
Find the 6th term.


Sagot :

Answer:

a₆ ≈ 25.284

Step-by-step explanation:

There is a common ratio between consecutive terms , that is

8 ÷ 6 = [tex]\frac{32}{3}[/tex] ÷ 8 = [tex]\frac{4}{3}[/tex]

This indicates the sequence is geometric with nth term

[tex]a_{n}[/tex] = a₁ [tex]r^{n-1}[/tex]

where a₁ is the first term and r the common ratio

Here a₁ = 6 and r = [tex]\frac{4}{3}[/tex] , then

a₆ = 6 × [tex](\frac{4}{3}) ^{5}[/tex] = 6 × [tex]\frac{1024}{243}[/tex] = [tex]\frac{6(1024)}{243}[/tex] ≈ 25.284 ( to the nearest thousandth )

Step-by-step explanation:

it is a geometric sequence.

the common ratio or factor is 4/3.

I got this by simply trying to get from the 2nd to the 3rd term.

8×x = 32/3

24x = 32

x = 32/24 = 16/12 = 8/6 = 4/3

s1 = 6

s2 = s1 × 4/3 = 6 × 4/3 = 24/3 = 8

s3 = s2 × 4/3 = s1 × 4/3 × 4/3 = 6 × 16/9 = 2 × 16/3 = 32/3

sn = s1 × (4/3)^(n-1)

s6 = 6 × (4/3)⁵ = 6 × 1024/243 = 2 × 1024/81 = 2048/81 =

= 25.284