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\log_(2) (x^(5)) = 1

Sagot :

altavistard

Answer:

Step-by-step explanation:

Let's convert this equation to exponential form.  Then:

 ^ \log_(2) (x^(5))

2                             = 2^1     This is valid because 2 is the base of both the logarithmic and exponential forms.  

Therefore:

x^5 = 2.  Taking the fifth root of both sides, we get:

x = 2^(2/5), which is approximately 1.32.

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