Answered

Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Connect with professionals ready to provide precise answers to your questions on our comprehensive Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

The area of a rectangle is 54 square feet. Find the length and width if the length is
three feet less than twice the width

Sagot :

devishri1977

Answer:

Width = 6 ft

Length = 9 ft

Step-by-step explanation:

Width =w

Length = 2w - 3

Area = 54 sq. ft

length *width = 54

(2w -3) *w = 54

2w² - 3w = 54

2w² - 3w - 54= 0

P = -108

Sum = -3

Factors = -12,9   {-12 + 9 = -3  & (-12)*9 = -108}

2w² - 12w + 9w -54 = 0

2w(w - 6) + 9(w- 6)=0

(w-6)(2w + 9) = 0

Ignore (2w + 9) as measure wont be negative

w -6 = 0

w = 6 ft

length = 2*6 - 3 = 12-3 = 9 ft

Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.