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A 3.6-kg goose floats on a lake with 46 % of its body below the 1000-kg/m3 water level. Determine the average density of the goose.

Sagot :

The average density of the goose on the given lake is 460 kg/m³.

The given parameters;

  • mass of the goose, m = 3.6 kg
  • fraction of the goose below the lake, = 46%
  • density of the water, ρ = 1000 kg/m³

The specific gravity of the goose is calculated as follows;

[tex]S.G = \frac{46}{100} = 0.46[/tex]

The density of the goose is calculated as follows;

[tex]S.G = \frac{\rho _{g}}{\rho_{w}} \\\\\rho_{g} = S.G \times \rho_{w}[/tex]

where;

  • [tex]\rho _{w}[/tex] is the density of water
  • [tex]\rho _{g}[/tex] is the density of the goose

The density of the goose is calculated as;

[tex]\rho _{g}= 0.46 \times 1000 \ kg/m^3\\\\\rho _{g}= 460 \ kg/m^3[/tex]

Thus, the average density of the goose on the given lake is 460 kg/m³.

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