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Sagot :
Answer:
empirical formula is C6H12O3
Explanation:
A sample of a compound is decomposed in the laboratory and produces
72.1 g carbon, 12.1 g hydrogen, and 48.0 g oxygen. Calculate the empirical formula of the compound.
divide the gm by the atomic mass and ratio the results
C=72.1/12.01 =6.00
H = 12.1/1.01 = 11,98 =~12
O =48.0/16 = 3
empirical formula is C6H12O3
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