Answered

Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Discover comprehensive solutions to your questions from a wide network of experts on our user-friendly platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

Tickets numbered 1−10 are drawn at random and placed back in the pile. Find the probability that at least one ticket numbered 2-6 is drawn if there are 4 drawings that occur. Round your answer to two decimal places.

Sagot :

fichoh

The probability that atleast one ticket labeled 2-6 is drawn is 0.94

Numbered ticket = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

Number of draws = 4

Required picks = {2, 3, 4, 5, 6}

Recall :

  • Probability = required outcome / Total possible outcomes

Probability of choosing a required ticket :

  • 5/10 = 1/2

Therefore, the probability that none of the required tickets is chosen :

  • (1/2 × 1/2 × 1/2 × 1/2) = 1/16

The probability that atleasr one ticket labeled 2-6 is drawn is :

1 - P(none is chosen) = 1 - 1/16 = 15/16 = 0.9375

Learn more :https://brainly.com/question/18405415

We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.