shielacalaguas
Answered

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When b = 3 and c = 4, b⁵c⁶/b³c³​

When B 3 And C 4 Bcbc class=

Sagot :

Kakitzu

Substitute the variables for the numbers. Then solve.

b⁵ = 3⁵ = 243

c⁶ = 4⁶ = 4096

b³ = 3³ = 27

c³ = 4³ = 64

(243)(4096)/(27)(64) = 576

Answer:

simplify the powers, so b^(5-3) * c^(6-3) =

b^2 * c^3 = 3^2 * 4^3 =

9 * 64 = 576

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