noodles0407
Answered

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The graph of a linear equation contains the points (6,7) and (-4,13) find another point that lies on the graph

Sagot :

StudiousStud3nt

Answer:

(10,4.6)

Step-by-step explanation:

We need to find the equation for the line first

Find the slope:

m = y2-y1/x2-x1

m = 13 - 7 / -4 - 6

m = 6 / -10

Now we need the y intercept (b)

subtitute one of the points into the equation

y = -6/10x + b

7 = -6/10(6) + b

7 = -3.6 + b

10.6 = b

Now we have the full equation for the line

y = -6/10x + 10.6

and we can input any value into x to find the y of the point

y = -6/10(10) + 10.6

y = -6 + 10.6

y = 4.6

Answer:

(11, 4)

Step-by-step explanation:

Find the slope = rise/ run  or (change in y values)/(change in x-values)

Using points (6, 7) and (-4, 13) ; Slope = (13 - 7)/(-4 - 6) = 6/-10 = -3/5

From this point if the slope is -3/5 this means the rise is -3 and the run 5.

remember that a negative rise you will move down on the rise from the point and a positive run means you will move across from the point.

Using point (6, 7) .

The run is the x movement on a graph so start at 6 and move to the right 5 places,  you in up at  x= 11.

The rise is the y movement on the graph so start at 7 and move down 3 places, you are at y = 4

Point (x, y) on the graph is (11, 4)

to check the problem

you from the slope = -3/5 . If you solve for "b"  in y = mx + b. The equation of the line in slope intercept form is y = -3/5x + 53/5.  Graph  the line and check the point or substitute any value for x and solve for y.

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