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If 8.77g of potassium iodide (KI) are dissolved in sufficient water to make 4.75L of solution, what is the molarity of the solution

Sagot :

Purplefox1212

Answer:

0.0111mol/L

Explanation:

M = n/V

We don't know n, but we know that n =mass/Molar mass, so:

n = 8.77g/166.0028 g/mol

n = 0.0528304342mol

M = n/V

M = 0.0528304342mol/ 4.75L

M = 0.111221967mol/L

Round to three sig figs if necessary: 0.0111mol/L

The molarity of the solution is 0.010M.

Molarity:

Molar concentration is a measure of the concentration of a chemical species, in particular of a solute in a solution, in terms of amount of substance per unit volume of solution.

Given:

Mass=8.77g

Volume= 4.75 L

To find:

Molarity=?

Firstly we need to calculate the number of moles.

Molar mass of KI=  166 g/mol

Given mass= 8.77 g

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} \\\\\text{Number of moles}=\frac{8.77}{166}= 0.05 \text{mol}[/tex]

Now, substituting the values in molarity formula which is given as:

[tex]\text{Molarity}=\frac{n}{V} \\\\\text{Molarity}=\frac{0.05}{4.75} =0.010M[/tex]

Therefore, the molarity of the solution is 0.010M.

Learn more:

brainly.com/question/19943363

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