Answered

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Equation of a line that goes through point (4,2) and perpendicular to -x+y=1

Sagot :

kevinclq0811

Answer:

y= -x + 6

Step-by-step explanation:

-x + y =1 ---> y = x+1

the line perpendicular to this line should have negative inverse slope

the slope is 1 so the negative inverse of 1 is -1

set up

y = -x +b

since it goes through (4,2)

then we have

2 = -4 +b

b=6

so the linear equation is y = -x+6

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