annabelle077
Answered

Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Ask your questions and receive precise answers from experienced professionals across different disciplines. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

A sample of an unknown gas occupies 5.51 L at 1.31 atm. What pressure would thisgas exert in a 0.520 L container if the temperature is held constant?

Sagot :

Purplefox1212

Answer:

13.9atm

Explanation:

Use Boyle's Law: P1V1 = P2V2

Manipulate the equation: P2 = P1V1/V2

Substitute the values: P2 = (1.31atm)(5.51L)/0.520L

P2 = 13.88096atm

Optionally round to 3 sig figs to get 13.9atm

Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.