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Sagot :
Hello gonzaleznoah570!
[tex] \huge \boxed{\mathbb{QUESTION} \downarrow}[/tex]
[tex] \large \tt\frac{48}{16} = \frac{ \boxed{}}{8} \\ [/tex]
[tex] \large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}[/tex]
Let's take the value inside the box as 'x'. So, now our equation becomes...
[tex] \tt \: \frac{48}{16} = \frac{x}{8} \\ [/tex]
Now, using cross multiplication, solve it.
[tex] \tt \: \frac{48}{16} = \frac{x}{8} \\ \tt \: 48 \times 8 = 16 \times x \\ \tt \: 384 = 16x \\ \tt \frac{384}{16} = x \\ \boxed{\boxed{ \bf \: 24 = x}}[/tex]
- The value of the [tex]\boxed{}\\[/tex] is 24.
__________________
Hope it'll help you!
ℓu¢αzz ッ
Hello There!
Question:-
Find the unknown value
Equation Given:-
[tex]\sf \dfrac{48}{16} = \dfrac{\boxed{}}{8} [/tex]
Solution:-
Let's us assume that the value of the unknown number be b.
The Equation would be :-
[tex]\sf \longmapsto \: \dfrac{48}{16} = \dfrac{b}{8} [/tex]
Firstly, Cross multiply :-
[tex]\sf \longmapsto \: (48)*(8)=b*(16)[/tex]
On Simplification of this equation :-
[tex]\sf \longmapsto384 = b*(16)[/tex]
[tex]\sf \longmapsto384 = 16b[/tex]
Overturn The equation given :-
[tex]\sf \longmapsto16b = 384[/tex]
Divide both sides by 16 :-
[tex]\sf \longmapsto \: \dfrac{16b}{16} = \dfrac{384}{16} [/tex]
On Simplification of this equation :-
Cancel 16 and 16, Result is 1b, which equals to b.
[tex]\sf \longmapsto \dfrac{ \cancel{16}b}{ \cancel16} = \dfrac{384}{16} [/tex]
Then cancel 384/16, which results to 24.
[tex]\sf \longmapsto \: b = \cancel\dfrac{384}{16} [/tex]
[tex]\sf \longmapsto \: b = 24[/tex]
Put the value of b (24) on 48/16 = b/8 :-
[tex]\sf \longmapsto \: \dfrac{48}{16} = \dfrac{24}{8} [/tex]
______________________________________
Henceforth,The unknown value is 24.
[tex]\boxed{ \bf \: \dfrac{48}{16} = \dfrac{24}{8} }[/tex]
________________________________
Please let me know if you have any questions.
~MisterBrian
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