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help need pls anewer 1-4​

Help Need Pls Anewer 14 class=

Sagot :

pjdemarco

Answer:

1. width is w. length is w + 26

2.

[tex]w \times (w + 26) < 2040[/tex]

3. the width must be less than 34

4. sure, if the width is 10, then the area is 360

Step-by-step explanation:

[tex]w \times (w + 26) < 2040[/tex]

1

devishri1977

Answer:

Step-by-step explanation:

1) Width = w ft

Length = ( w + 26 ) ft

2) Area of floor = length *width

(w + 26)*w < 2040

w*w + 26*w < 2040

w² + 26w - 2040 < 0

3) w² - 34w + 60w - 2040 < 0

w(w - 34) + 60(w - 34) < 0

(w -34)(w  + 60) < 0

Ignore w +60 as width wont have a negative value.

w - 34 < 0

w < 34

l = 33 + 26 = 59

Width = 33 and length= 59

Area = length * width = 33 *  59  = 1947 sq. ft

Area ≤ 1947

4) Yes.

If width = 10 , length = 26 + 10 = 36

36* 10 = 360 sq. ft.

So, if it possible to have a n area of 360 sq. ft

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