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Sagot :
Explanation:-
★(i).
A = { 1,2}
⇛ n (A ) = 2
B = { 3,4,5,6}
⇛ n (B) = 4
n(A)+n(B) = 2+4 = 6
★(ii).
The symbol ⇛ means Implies
★(iii).
A = Phi = {}
B = phi = {}
AUB = { } U { } = { }
AUB = phi = { }
(iv).
AUB = BUA is called Commutative law in sets uner union .
★(v).
Null set = Void set = Empty set = { }
Number of elements in the empty set = 0
⇛ Cardinal number of null set is zero (0)
★(vi). If AUB = B then B is the super set and A is the sub set of B
★(vii). A = { 1,2,3,4}
B = {2,4,6,8}
A-B = {1,2,3,4} - { 2,4,6,8}
=> A-B = { 1,3}
★(viii). n(AUB) = 8
n(A) = 6
n(B) = 4
We know that
n(AnB) = n(A)+n(B)-n(AUB)
⇛ n(AnB) = 6+4-8
⇛n(AnB) = 10-8
⇛ n(AnB) = 2
or n(AUB)+n(AnB) = n(A)+n(B)
⇛ 8+ n(AnB) = 6+4
⇛ 8+ n(AnB) =10
⇛ n(AnB) = 10-8
⇛ n(AnB) = 2
Therefore, n(AnB) = 2
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