Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Our platform provides a seamless experience for finding precise answers from a network of experienced professionals. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
Answer:
[tex] {x}^{2} + 5x + 4 \\ \\ {x}^{2} + 4x + 1x + 4 \\ \\ x(x + 4) + 1(x + 4) \\ \\ (x + 4)(x + 1) \\ \\ {x}^{2} - 8x - 7 \\ \\ {x}^{2} - 7x + 1x + 7 \\ \\ x(x - 7) + 1( \times - ) \\ \\ (x - 7)(x + 7)[/tex]
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
Question 1 ~
- [tex] {x}^{2} + 5x + 4[/tex]
- [tex] {x}^{2} + 4x + x + 4[/tex]
- [tex]x( x + 4) + 1(x + 4)[/tex]
- [tex](x + 4)(x + 1)[/tex]
So, the roots are ~
- [tex] \boxed{x = - 4}[/tex]
and
- [tex] \boxed{x = - 1}[/tex]
Question 2 ~
- [tex] {x}^{2} - 8x - 7[/tex]
let's use the quadratic formula for this one ~
(because it can't be solved through middle term split method)
[tex] \boxed{ \mathrm{ \dfrac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a} }}[/tex]
where,
- b = -8 (Coefficient of x)
- a = 1 (Coefficient of x²)
- c = -7 (Constant)
now, let's plug the values to find the roots ~
- [tex] \dfrac{ - ( - 8) \pm \sqrt{( - 8) {}^{2} - (4 \times 1 \times - 7) } }{2 \times 1} [/tex]
- [tex] \dfrac{8 \pm \sqrt{64 - ( - 28)} }{2} [/tex]
- [tex] \dfrac{8 \pm \sqrt{64 + 28} }{2} [/tex]
- [tex] \dfrac{8 \pm \sqrt{92} }{2} [/tex]
- [tex] \dfrac{8 \pm4 \sqrt{23} }{2} [/tex]
- [tex] \dfrac{2(4 \pm2 \sqrt{23)} }{2} [/tex]
- [tex]4 \pm2 \sqrt{23} [/tex]
So, the roots are ~
- [tex] \boxed{x = 4 + 2 \sqrt{23} }[/tex]
and
- [tex] \boxed{x = 4 - 2 \sqrt{23} }[/tex]
We appreciate your time. Please come back anytime for the latest information and answers to your questions. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.