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Sagot :
Answer:
Step-by-step explanation:
[tex]2x - 10^o + 2x + 30^o + x + 10^o + 50^o = 180^o \\\ 5x + 80^o = 180^o \\\ 5x = 180^o - 80^o \\\ 5x = 100^o \\\ x = \frac{100^o}{5} \\\\ x = 20°[/tex]
I hope I've helped you.
Explanation:-
From the given figure :
∠AOB = 50°
∠BOC = x+10°
∠COD = 2x+30°
∠DOE = 2x-10°
We know that
The sum of the angles lie on the same line = 180°
⇛ ∠AOB + ∠BOC + ∠COD + ∠DOE = 180°
⇛ 50°+x+10°+2x+30°+2x-10° = 180°
⇛ 5x+80° = 180°
⇛ 5x = 180°-80°
⇛ 5x = 100°
⇛ x = 100°/5
⇛ x = 20°
∴ x = 20°
Now,
The measure of ∠BOC = x+10°
= 20°+10°
= 30°
The measure of ∠COD = 2x+30°
= 2(20°)+30°
= 40°+30°
= 70°
The measure of ∠DOE = 2x-10°
=2(20°)-10°
= 40°-10°
= 30°
Answer:-
The measure of ∠BOC = 30°
The measure of ∠COD = 70°
The measure of ∠DOE = 30°
Remember:-The sum of the angles lie on the same line is 180°
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