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A rental car company charges $75.77 per day to rent a car and $0.07 for every mile

driven. Scarlett wants to rent a car, knowing that:

• She plans to drive 325 miles.

She has at most $340 to spend.

Which inequality can be used to determine d, the maximum number of days Scarlett

can afford to rent for while staying within her budget?

340 < 75.77d + 22.75

340 < 75.77(d + 22.75)

Submit Answer

340 > 75.77(d + 22.75)

340 > 75.770 + 22.75

Sagot :

MrRoyal

The daily rent is an illustration of a linear inequality.

The inequality is (d) [tex]\mathbf{340 > 75.77d + 22.75 }[/tex]

The daily charge is given as:

[tex]\mathbf{Daily = 75.77}[/tex]

The rate is:

[tex]\mathbf{Rate = 0.07}[/tex]

Let the number of days be d.

So, the total charges is:

[tex]\mathbf{Total = Daily \times d + Rate \times Miles}[/tex]

This gives

[tex]\mathbf{Total = 75.77 \times d + 0.07\times 325}[/tex]

[tex]\mathbf{Total = 75.77 \times d + 22.75}[/tex]

From the question, we understand that he has at most $340 to spend.

At most means <=

So, we have:

[tex]\mathbf{75.77 \times d + 22.75 \le 340}[/tex]

[tex]\mathbf{75.77d + 22.75 \le 340}[/tex]

Rewrite as:

[tex]\mathbf{340 > 75.77d + 22.75 }[/tex]

Hence, the inequality is (d) [tex]\mathbf{340 > 75.77d + 22.75 }[/tex]

Read more about linear inequalities at:

https://brainly.com/question/11897796

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