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What are the potential solutions of In(x2 - 25) = 0?

x=113

X-5

x=126

X-010


Sagot :

Step-by-step explanation:

ln(x² - 25) = 0

x² - 25 ≤ 0

x² ≤ 25

x ≥ -5 or x ≤ 5

-5 ≤ x ≤ 5

ln(x² - 25) = 0 , -5≤x≤5

x² - 25 = 1

x² = 26

x = -√26 and √26 are the solution of the equation