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A strechy material with a spring constant of 42 N/m is stretched 3.6 cm from its equilibrium length. What is the magnitude of the resulting spring force

Sagot :

k : spring constant
X : distance from equilibrium position
F = 1/2 x k x X^2
F = 1/2 x 42 x 0.036^2
F = 0.027 N