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A power plant running at 39 % efficiency generates 330 MW of electric power. Part A At what rate (in MW) is heat energy exhausted to the river that cools the plant

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xero099

516.154 megawatts of heat are exhausted to the river that cools the plant.

By definition of energy efficiency, we derive an expression for the energy rate exhausted to the river ([tex]Q_{out}[/tex]), in megawatts:

[tex]Q_{out} = Q_{in} - W[/tex]

[tex]Q_{out} = \left(\frac{1}{\eta}-1 \right)\cdot W[/tex](1)

Where:

  • [tex]\eta[/tex] - Efficiency.
  • [tex]W[/tex] - Electric power, in megawatts.

If we know that [tex]\eta = 0.39[/tex] and [tex]W = 330\,MW[/tex], then the energy rate exhausted to the river is:

[tex]Q_{out} = \left(\frac{1}{0.39}-1 \right)\cdot (330\,MW)[/tex]

[tex]Q_{out} = 516.154\,MW[/tex]

516.154 megawatts of heat are exhausted to the river that cools the plant.

We kindly to check this question on first law of thermodynamics: https://brainly.com/question/3808473

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