516.154 megawatts of heat are exhausted to the river that cools the plant.
By definition of energy efficiency, we derive an expression for the energy rate exhausted to the river ([tex]Q_{out}[/tex]), in megawatts:
[tex]Q_{out} = Q_{in} - W[/tex]
[tex]Q_{out} = \left(\frac{1}{\eta}-1 \right)\cdot W[/tex](1)
Where:
- [tex]\eta[/tex] - Efficiency.
- [tex]W[/tex] - Electric power, in megawatts.
If we know that [tex]\eta = 0.39[/tex] and [tex]W = 330\,MW[/tex], then the energy rate exhausted to the river is:
[tex]Q_{out} = \left(\frac{1}{0.39}-1 \right)\cdot (330\,MW)[/tex]
[tex]Q_{out} = 516.154\,MW[/tex]
516.154 megawatts of heat are exhausted to the river that cools the plant.
We kindly to check this question on first law of thermodynamics: https://brainly.com/question/3808473
