Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Explore a wealth of knowledge from professionals across different disciplines on our comprehensive platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
divide both sides by 4x:
x^2-2x+1=0
You can either factor, complete the square, or use the quadratic formula.
I'll factor this into (x-1)(x-1)=0
x-1=0, so x=1
x^2-2x+1=0
You can either factor, complete the square, or use the quadratic formula.
I'll factor this into (x-1)(x-1)=0
x-1=0, so x=1
First of all, your second term is already wrong. When you divided 8x² by 4 ,
you should have written 2x² , not 4x² .
Make that correction, and then divide the whole thing by 'x'.
Then you'll have x² - 2x + 1 = 0 .
You should have no trouble solving that one,
(especially since it's a perfect square)
That gives you two (equal) solutions. But you should also ask yourself:
"Self ! Where is the third solution ? A cubic equation like the original
one needs three solutions."
I'll give you that one:
Look over the original equation, and look at what happens to it when x = 0 .
Then the left side becomes zero, and the equation is 0 = 0 . Since that's a
true statement, " x = 0 " is another solution of the cubic equation, and now
you have all three of them.
We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.