user1828281
Answered

At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

given that R=0.0821 (L•atm) / (mol•K) how many moles must be in a 2L container at 1.8 atmospheres with a temperature of 270K

Sagot :

Eduard22sly

The number of mole in the container at 1.8 atm with a temperature of 270 K is 0.162 mole.

From the question given above, the following data were obtained:

Gas constant (R) = 0.0821 atm.L/Kmol

Volume (V) = 2 L

Pressure (P) = 1.8 atm

Temperature (T) = 270 K

Number of mole (n) =?

Using the ideal gas equation, we can obtain the number of mole in the container as illustrated below:

PV = nRT

1.8 × 2 = n × 0.0821 × 270

3.6 = n × 22.167

Divide both side by 22.167

n = 3.6 / 22.167

n = 0.162 mole

Therefore, the number of mole in the container is 0.162 mole

Learn more: https://brainly.com/question/9731218

We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.