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given that R=0.0821 (L•atm) / (mol•K) how many moles must be in a 2L container at 1.8 atmospheres with a temperature of 270K

Sagot :

Eduard22sly

The number of mole in the container at 1.8 atm with a temperature of 270 K is 0.162 mole.

From the question given above, the following data were obtained:

Gas constant (R) = 0.0821 atm.L/Kmol

Volume (V) = 2 L

Pressure (P) = 1.8 atm

Temperature (T) = 270 K

Number of mole (n) =?

Using the ideal gas equation, we can obtain the number of mole in the container as illustrated below:

PV = nRT

1.8 × 2 = n × 0.0821 × 270

3.6 = n × 22.167

Divide both side by 22.167

n = 3.6 / 22.167

n = 0.162 mole

Therefore, the number of mole in the container is 0.162 mole

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