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If you have a 4.6 L of gas in a piston at a pressure of 1.2 atm and compress 2p the gas until its volume is 2.6 L, what will the new pressure inside the piston be? ​

Sagot :

Purplefox1212

Answer:

2.12atm

Explanation:

Boyle's Law: P1V1 = P2V2

Manipulate to solve for unknown: P2 = P1V1/V2

Substitute values:  P2=(1.2atm)(4.6L)/2.6L

P2 = 2.1230769atm

Round to 3 sig figs to get 2.12atm

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