Answered

Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

A student added 0.90 mL of 0.50 M NaOH, 0.70 mL of 1.0 M HA, and 0.40 mL water to their trial 1. How many moles of NaOH did they add

Sagot :

pstnonsonjoku

There are 0.00045 moles of sodium hydroxide that were added in the solution.

From the question, we have the following information;

Volume of sodium hydroxide =  0.90 mL or 0.00009 L

Concentration of sodium hydroxide = 0.50 M

We  know that;

Number of moles = volume of solution × concentration of solution

Substituting values;

The number of moles of sodium hydroxide added = 0.9/1000 L ×  0.50

= 0.00045 moles

Learn more: https://brainly.com/question/4612545

Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.