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Sagot :
A collision which is inelastic is one in which the internal energy changes.
All the kinetic energy is dissipated
Reasons:
The given parameters are;
The mass of one car = The mass of the second car in the collision = m
The type of collision = Inelastic collision
The speed of each of the cars in the collision = v and -v
Solution:
In an inelastic collision, we have;
[tex]m_1 \cdot v_{1i} + m_2 \cdot v_{2i} = (m_1 + m_2) \cdot v_f[/tex]
Therefore, we get;
[tex]m \cdot v_{i} -m \cdot v_{i} = 0= 2 \cdot m \cdot v_f[/tex]
Which gives;
[tex]v_f = 0[/tex]
The collision is an example of a perfectly inelastic collision, and the final velocity after the collision is zero.
The change in the energy is [tex]\Delta K.E. = K.E._{final} - K.E._{initial}[/tex]
[tex]K.E._{initial}[/tex] = 0.5·m·v² + 0.5·m·v² = m·v²
ΔK.E. = 0.5·(2·m)×0 - 0.5·m·v² + 0.5·m·v² = -m·v²
ΔK.E. = -m·v²
The negative sign stands for energy given out, which gives;
The energy dissipated = m·v² (The total initial kinetic energy)
Therefore, all the kinetic energy is dissipated
Learn more here:
https://brainly.com/question/19106769
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