Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
Answer:
52N
Explanation:
v=SQRT(T/μ), μ=pA, A=πr^2
v=SQRT(T/pπr^2)
v^2=T/pπr^2
v^2*pπr^2=T
34^2*2700*π*0.0023^2=T
T=52N
The tension on the aluminum wire at the given density is 52.02 N.
Tension in the wire
The tension in the wire is calculated using the following formulas;
[tex]v = \sqrt{\frac{T}{\mu} }[/tex]
where;
- v is speed of the sound wave
- T is the tension in the wire
- μ is mass per unit length
Area of the aluminum wire
A = πd²/4
A = π x (4.6 x 10⁻³)²/4
A = 1.66 x 10⁻⁵ m²
Mass per unit length of the wire
μ = ρA
μ = 2700 kg/m³ x 1.66 x 10⁻⁵ m²
μ = 0.045 kg/m
Tension on the wire
[tex]34 = \sqrt{\frac{T}{0.045} } \\\\34^2 = \frac{T}{0.045}\\\\T = (34^2)(0.045)\\\\T = 52.02 \ N[/tex]
Thus, the tension on the aluminum wire at the given density is 52.02 N.
Learn more about tension on wire here: https://brainly.com/question/14336853
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.