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Sagot :
Answer:
610 virus cells
Step-by-step explanation:
let 10,000,000 be y And 12hrs be z and the cells left at the end of the week be x
I.e
[tex]x = y { \binom {1} {2}} ^{ \binom{t}{tx} } [/tex]
where tx is how long it takes for 1/2 of it to decay and t is the number of hours it's supposed to decay
So
[tex]x \: = \: 10000000 \: \times {{\frac{1}{2}}} ^{ \frac{24 \times 7}{12} } [/tex]
t is 7 weeks × 24 to convert to hours
so, therefore, 24 × 7 ÷ 12 is 14 [tex]x = 10000000 \times \frac{1}{ {2}^{14} } [/tex]
so 10,000,000 ÷ 2^14
10,000,000 ÷ 16,348 = 610.4
therefore there are approximately 610 viruses left after one week
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