Answered

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determine the zeros of the function f(x) = 2(x – 6)^2 – 4

Sagot :

Answer:

x = 6 ± [tex]\sqrt{2}[/tex]

Step-by-step explanation:

To find the zeros equate f(x) to zero , that is

2(x - 6)² - 4 = 0 ( add 4 to both sides )

2(x - 6)² = 4 ( divide both sides by 2 )

(x - 6)² = 2 ( take square root of both sides )

x - 6 = ± [tex]\sqrt{2}[/tex] ( add 6 to both sides )

x = 6 ± [tex]\sqrt{2}[/tex]

The zeros are x = 6 - [tex]\sqrt{2}[/tex] , x = 6 + [tex]\sqrt{2}[/tex]

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