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At what temperature (in K) will 3.5 moles of gas occupy 2.7 L at 1.5 atm? HELP PLEASE!

Sagot :

samueladesida43

3.5 moles of a gas will occupy 2.7 L at 1.5 atm at a temperature of 14.1K

IDEAL GAS LAW:

  • The temperature of a gas can be calculated using the ideal gas law equation:

PV = nRT

Where;

  1. P = pressure (atm)
  2. V = volume (L)
  3. n = number of moles (mol)
  4. R = gas law constant (0.0821 Latm/molK)
  5. T = temperature (K)

  • According to this question, P = 1.5atm, V = 2.7L, n = 3.5moles, T = ?

  • 1.5 × 2.7 = 3.5 × 0.0821 × T

  • 4.05 = 0.28735T

  • T = 4.05 ÷ 0.28735

  • T = 14.1K

  • Therefore, 3.5 moles of a gas will occupy 2.7 L at 1.5 atm at a temperature of 14.1K

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