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A sample of a compound has been analyzed and found to contain the following:
38.71% carbon, 9.75% hydrogen, and 51.54% g oxygen. If the molar mass of
the compound is determined by experiment to be between 62 and 63 g, what are
the empirical and molecular formulas of the compound?

Sagot :

Answer:

CH3O formula, C2H6O2 ACTUAL FORMULA

Explanation:

A sample of a compound has been analyzed and found to contain the following:

38.71% carbon, 9.75% hydrogen, and 51.54% g oxygen. If the molar mass of

the compound is determined by experiment to be between 62 and 63 g, what are the empirical and molecular formulas of the COMPOUND

empitical

take 100 gm of the compound

f O  Divide by atomi wt of O to get moles

51.54/ 16.0 = 3.22

now  if there is 1 atom of  C and one of O, there will be 3 of H, so

CH3O is the empirical formula

the molar mass of the compound  is 62-63.  the mass of CH3O is

12 + 16 +3 = 31

2 X31 =62

so the compound is 2 times CH3O or C2H6O2

it most likely is

Ethylene glycol (name IUPAC: ethane-1,2-diol) is an organic formulated compound (CH2OH)2.