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Working on this for literally the whole day, don’t understand, looking for answers, struggling,
and very tired I need help please.

Part c please help

Working On This For Literally The Whole Day Dont Understand Looking For Answers Struggling And Very Tired I Need Help Please Part C Please Help class=

Sagot :

maniknandini

Answer:

4

Step-by-step explanation:

PART C:

Another theorem states that in a right triangle, the altitude from the right angle to the hypotenuse divides the hypotenuse into two segments.  Each leg of the right triangle is the geometric mean of the hypotenuse and the segment of the hypotenuse that is adjacent to the leg.

This means the ED, a leg of the right triangle,  is the geometric mean of EF, the length of the hypotenuse  (8) and the EG, the segment adjacent to the leg (2)

ED = Geometric mean = [tex]\sqrt{EG * EF}[/tex]

= [tex]\sqrt{2 * 8}[/tex]

= [tex]\sqrt{16}[/tex]

= 4

ED = 4

Sweetylyx

Answer:

The person above is correct

Step-by-step explanation:

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