At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Get quick and reliable solutions to your questions from knowledgeable professionals on our comprehensive Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

7+6 (mod 5) =

2+1 (mod 5) =

20 (mod 11) =

35 (mod 11) =

20 (mod 11) =​

Sagot :

Answers:

  • 3
  • 3
  • 9
  • 2
  • 9

======================================

Explanation:

7+6 = 13. Divide this over 5 to get 13/5 = 2 remainder 3. The quotient 2 is something we don't care about. We only worry about the remainder. Therefore 7+6 = 3 (mod 5)

-------------

2+1 = 3 (mod 5) for similar reasoning as above. 3/5 = 0 remainder 3.

-------------

20 = 9 (mod 11) since 20/11 = 1 remainder 9. Imagine you had 20 cookies and 11 friends. Each friend would get 1 whole cookie (quotient) and there could be 9 left over (remainder).

-------------

35/11 = 3 remainder 2

Or you could use repeated subtraction like so to find the remainder

35-11 = 24

24-11 = 13

13-11 = 2

The last result (2) is smaller than 11, so we stop here and this is the remainder.

Therefore, 35 = 2 (mod 11)

--------------

Here's another way to think of it. Consider you have $35 in your pocket. Let's say a store is selling trinkets for $11 each. We can pose these key questions:

  • What is the most number of trinkets you can buy?
  • If you buy that max amount, how much will you have left over?

The answer to the first question is 3 trinkets because 3*11 = 33 dollars is under the budget of $35. The amount left over is 35-33 = 2 dollars which is the remainder. It's not larger than 11, so we cannot buy any more trinkets at this point.

We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.