tornyiegrace
Answered

Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

A tractor can apply a force of 15000 Newtons to get out of a mud pit. The
mud is resisting the tractor with a force of 11250 Newtons. The tractor
manages to accelerate out of the mud with a rate of 1.25 m/s^2. What is
the mass of the tractor?

Sagot :

Ok you divide the force of friction by the applied force (11250/15000) and that gives the coefficient of friction, coefficient of friction is always between 0 and 1, when divided out you get 0.75 set that equal to the force of friction equation (Ff=(g)(m)(coefficient of friction)) so you get 11250=9.81(0.75)m and then you simplify to 11250/(9.81)(0.75) and you get 1529 kg with sig figs I’d say you can do 1530 kg, by the way the g is for acceleration produced by gravity which is 9.81 on earth.
We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.