Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

A tractor can apply a force of 15000 Newtons to get out of a mud pit. The
mud is resisting the tractor with a force of 11250 Newtons. The tractor
manages to accelerate out of the mud with a rate of 1.25 m/s^2. What is
the mass of the tractor?


Sagot :

Ok you divide the force of friction by the applied force (11250/15000) and that gives the coefficient of friction, coefficient of friction is always between 0 and 1, when divided out you get 0.75 set that equal to the force of friction equation (Ff=(g)(m)(coefficient of friction)) so you get 11250=9.81(0.75)m and then you simplify to 11250/(9.81)(0.75) and you get 1529 kg with sig figs I’d say you can do 1530 kg, by the way the g is for acceleration produced by gravity which is 9.81 on earth.
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.