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What is the radius of a sphere with a volume of 28526^3 to the nearest tenth of an inch?

Sagot :

Assuming you meant inches^3, V=4/3pir^3, substituting gives 28526=4/3pir^3 which simplifies to (3)(28526)/(4pi) which is equal to 6810 taking the cube root gives us the radius, 18.95
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