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The function f(x) = −(x + 5)(x + 1) is shown. On a coordinate plane, a parabola opens down. It goes through (negative 5, 0), has a vertex at (negative 3, 4), and goes through (negative 1, 0). What is the range of the function? all real numbers less than or equal to 4 all real numbers less than or equal to −3 all real numbers greater than or equal to 4 all real numbers greater than or equal to −3 Mark this and return

Sagot :

djtwinx017

Answer:

All real numbers less than or equal to 4.

f(x) ≤ 4

Interval notation:  (-∞, 4]

Step-by-step explanation:

Given the quadratic function, f(x) = -(x + 5)(x + 1), where the vertex occurs at point, (-3, 4):

Since the graph of the parabola opens down, then it means that the vertex  is its maximum point. In reference to the vertical points on the graph (i.e., the range values), then the vertex sets the maximum range value of k = 4. This implies that the maximum possible range value is from negative infinity to positive 4.

Therefore, the range of the function is: all real numbers less than to or equal to 4.

f(x) ≤ 4

Interval notation: (- ∞, 4]

Answer:

its A on edge

Step-by-step explanation:

Just took the test

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