Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
Split up the integrand into partial fractions:
(31 - x)/(x² + x - 20) = (31 - x)/((x + 5)(x - 4))
= a/(x + 5) + b/(x - 4)
= (a (x - 4) + b (x + 5))/((x + 5)(x - 4))
= (5b - 4a + (a + b) x)/((x + 5)(x - 4))
Then a + b = -1 and 5b - 4a = 31. Solving for a and b yields a = -4 and b = 3, so
(31 - x)/(x² + x - 20) = -4/(x + 5) + 3/(x - 4)
Now integrating is trivial; the antiderivative is
-4 ln|x + 5| + 3 ln|x - 4| + C
and by the fundamental theorem of calculus, we end up with
[tex]\displaystyle \int_0^1 \frac{31-x}{x^2+x-20} \, dx = (-4\ln|1+5|+3\ln|1-4|) - (-4\ln|0+5|+3\ln|0-4|) \\\\ = -4\ln(6) + 3\ln(3) + 4\ln(5) - 3\ln(4) \\\\ = \ln\left(\frac{3^3\cdot5^4}{4^3\cdot6^4}\right) \\\\ = \ln\left(\frac{625}{3072}\right) \approx -1.592[/tex]
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.