Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Explore a wealth of knowledge from professionals across various disciplines on our comprehensive Q&A platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
a) The x-intercepts are 5 and -2.
You can find this by setting x to 0.
So, 0 = -5 is basically 5 and 0 = 2 is -2.
b) The x-intercepts are 4 and 3.
For this problem, you have to factor the function first. It would be x=(x-4)(x-3) since -4 and -3 both add to -7 and multiply to 12, which is part of the -7x and the 12 in the equation. To find the x-intercepts, just do the same thing as I explained for a.
You can find this by setting x to 0.
So, 0 = -5 is basically 5 and 0 = 2 is -2.
b) The x-intercepts are 4 and 3.
For this problem, you have to factor the function first. It would be x=(x-4)(x-3) since -4 and -3 both add to -7 and multiply to 12, which is part of the -7x and the 12 in the equation. To find the x-intercepts, just do the same thing as I explained for a.
1) For number 1, your x intercepts will be 5 and -2 as your signs always switch.
2) you can solve your second function through a variety of ways but I like to use quadratic formula which gets you that your x intercepts are 3 and 4
2) you can solve your second function through a variety of ways but I like to use quadratic formula which gets you that your x intercepts are 3 and 4
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.