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Sagot :
a) The x-intercepts are 5 and -2.
You can find this by setting x to 0.
So, 0 = -5 is basically 5 and 0 = 2 is -2.
b) The x-intercepts are 4 and 3.
For this problem, you have to factor the function first. It would be x=(x-4)(x-3) since -4 and -3 both add to -7 and multiply to 12, which is part of the -7x and the 12 in the equation. To find the x-intercepts, just do the same thing as I explained for a.
You can find this by setting x to 0.
So, 0 = -5 is basically 5 and 0 = 2 is -2.
b) The x-intercepts are 4 and 3.
For this problem, you have to factor the function first. It would be x=(x-4)(x-3) since -4 and -3 both add to -7 and multiply to 12, which is part of the -7x and the 12 in the equation. To find the x-intercepts, just do the same thing as I explained for a.
1) For number 1, your x intercepts will be 5 and -2 as your signs always switch.
2) you can solve your second function through a variety of ways but I like to use quadratic formula which gets you that your x intercepts are 3 and 4
2) you can solve your second function through a variety of ways but I like to use quadratic formula which gets you that your x intercepts are 3 and 4
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