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Sagot :
3(x-1)^2 +2
This is your answer in vertex form, your h and k values are the vertex. Solving the function by using b/2a, we get that h is 1. ( in the equation 3 is your a, 6 is b and 5 is c.). ( 6/2(3)) = 1. We can then plug in 1 as x into the original equation and get positive 2 ( 3(1)^2 -6(1) +5) = 3-6+5 = 2. This is your vertex. In the function, your a value will always stay the same as this is your shrink or stretch. In this case, a is 3 so it will go outside the parenthesis. Put that all together and you get the function above.
Hope this helps :)
This is your answer in vertex form, your h and k values are the vertex. Solving the function by using b/2a, we get that h is 1. ( in the equation 3 is your a, 6 is b and 5 is c.). ( 6/2(3)) = 1. We can then plug in 1 as x into the original equation and get positive 2 ( 3(1)^2 -6(1) +5) = 3-6+5 = 2. This is your vertex. In the function, your a value will always stay the same as this is your shrink or stretch. In this case, a is 3 so it will go outside the parenthesis. Put that all together and you get the function above.
Hope this helps :)
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