Answered

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Does anyone know how to do this?

Does Anyone Know How To Do This class=

Sagot :

devishri1977

Answer:

A

Step-by-step explanation:

[tex]\dfrac{f(x)}{g(x)}=\dfrac{x+1}{x^{2}-x}\\f(x) = \dfrac{x+1}{x^{2}-x}*g(x)\\\\\dfrac{2}{x}*\dfrac{x^{2}-x}{x+1}=g(x)\\\\\\\dfrac{2}{x}*\dfrac{x(x-1)}{x+1}=g(x)\\\\\\\dfrac{2(x-1)}{x+1}=g(x)\\\\\[/tex]

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