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What are the roots of this quadratic equation?-10x^2+12x-9=0

Sagot :

devishri1977

Answer:

Step-by-step explanation:

-10x² + 12x - 9 = 0

Multiply the whole equation by (-1)

10x² - 12x + 9 = 0

a = 10  ; b = -12 ; c = 9

D = b² - 4ac = (-12)² - 4*10*9

   = 144 - 360

    = -216

√D = √-216 = [tex]\sqrt{2*2 * 3 * 3 * 2 *3 * i^{2}}[/tex]

       [tex]= 2*3*i*\sqrt{3*2}\\\\= 6i \sqrt{6}[/tex]

Roots = [tex]\frac{-b + \sqrt{D}}{2a} ; \frac{-b-\sqrt{D}}{2a}[/tex]

          [tex]= \dfrac{-[-12]+6i\sqrt{6}}{2*10} \ ; \ \dfrac{-[-12] - 6i\sqrt{6}}{2*10}\\\\= \dfrac{12+6i\sqrt{6}}{20} ; \ \dfrac{12-6i\sqrt{6}}{20}\\\\\\= \dfrac{2*(6+3i\sqrt{6}}{20} ; \ \dfrac{2*(6-3i\sqrt{6}}{20}\\\\=\dfrac{6+3i\sqrt{6}}{10} ; \dfrac{6-3i\sqrt{6}}{10}[/tex]

Answer:

Step-by-step explanation: Plato :)

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