Answered

Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Experience the convenience of getting accurate answers to your questions from a dedicated community of professionals. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

What are the roots of this quadratic equation?-10x^2+12x-9=0

Sagot :

devishri1977

Answer:

Step-by-step explanation:

-10x² + 12x - 9 = 0

Multiply the whole equation by (-1)

10x² - 12x + 9 = 0

a = 10  ; b = -12 ; c = 9

D = b² - 4ac = (-12)² - 4*10*9

   = 144 - 360

    = -216

√D = √-216 = [tex]\sqrt{2*2 * 3 * 3 * 2 *3 * i^{2}}[/tex]

       [tex]= 2*3*i*\sqrt{3*2}\\\\= 6i \sqrt{6}[/tex]

Roots = [tex]\frac{-b + \sqrt{D}}{2a} ; \frac{-b-\sqrt{D}}{2a}[/tex]

          [tex]= \dfrac{-[-12]+6i\sqrt{6}}{2*10} \ ; \ \dfrac{-[-12] - 6i\sqrt{6}}{2*10}\\\\= \dfrac{12+6i\sqrt{6}}{20} ; \ \dfrac{12-6i\sqrt{6}}{20}\\\\\\= \dfrac{2*(6+3i\sqrt{6}}{20} ; \ \dfrac{2*(6-3i\sqrt{6}}{20}\\\\=\dfrac{6+3i\sqrt{6}}{10} ; \dfrac{6-3i\sqrt{6}}{10}[/tex]

Answer:

Step-by-step explanation: Plato :)

View image carriekline
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.