Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Get quick and reliable answers to your questions from a dedicated community of professionals on our platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

Given a circle with radius of 3 cm. We drew two chords that are perpendicular to each other. One chord is 1 cm, the other is 2 cm away from the centre of the circle. Let us denote the areas of the four parts with x, y.z. v. What will be the area of (x+z)-(y+v)?



Given A Circle With Radius Of 3 Cm We Drew Two Chords That Are Perpendicular To Each Other One Chord Is 1 Cm The Other Is 2 Cm Away From The Centre Of The Circl class=

Sagot :

9514 1404 393

Answer:

  8 cm²

Step-by-step explanation:

If you reflect the drawn lines across the center of the circle, you can determine that the central rectangle is 2 cm wide and 4 cm high. Its area is the difference described by the expression ...

  (x +z) -(y +v) = (2 cm)(4 cm) = 8 cm²

__

The attached figure shows the areas of the individual non-overlapping regions. Comparing this to the original drawing you can see that the labels are shown properly.

The four upper right areas total to x. The two of those above the horizontal line total to v, so the right-center two areas are x-v. The rightmost center area is y-z, so the central rectangle is (x -v) -(y -z) = (x +z) -(y +v).

View image sqdancefan