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The table below shows all the possible outcomes when Henry spins two fair spinners. Spinner A is labelled with sections D, M and Q. Spinner B is labelled with sections 1, 2, 3, 4 and 5. a) What should go in the empty box in the table? b) Calculate P(Q, 4). Give your answer as a fraction in its lowest terms. ​

The Table Below Shows All The Possible Outcomes When Henry Spins Two Fair Spinners Spinner A Is Labelled With Sections D M And Q Spinner B Is Labelled With Sect class=

Sagot :

reinhard10158

Step-by-step explanation:

a)

well, logically, it must be M, 2

b)

this is a combined probability for one single pair of possible outcomes.

there are 15 pairs, all with the same probability.

so, P(Q, 4) = number of desired outcomes / number of possible outcomes = 1/15

as combined probability we can also say the probability to get 4 on one wheel is 1/5, and the probabilty to get Q on the other wheel is 1/3

so, P(Q, 4) = 1/3 × 1/5 = 1/15

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