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Sagot :
Answer:
[tex]15^{n-1}[/tex]
Step-by-step explanation:
First , Let's find the common ratio of this sequence.
[tex]\frac{15}{3}=5\\\frac{75}{15} = 5\\\frac{375}{75} = 5[/tex]
SO,
r = 5
Now let's use this formula to find the n th term
[tex]T_n = ar^{n-1}[/tex]
Here,
a = first term
r = common ratio
Let's find,
[tex]T_n = 3*5^{n-1}[/tex]
[tex]T_n =15^{n-1}[/tex]
Therefore,
the n th term is,
[tex]15^{n-1}[/tex]
Hope this helps you.
Let me know if you have any other questions :-)
Answer:
[tex]a_{n}[/tex] = 3[tex](5)^{n-1}[/tex]
Step-by-step explanation:
There is a common ratio between consecutive terms , that is
15 ÷ 3 = 75 ÷ 15 = 375 ÷ 75 = 5
This indicates the sequence is geometric with nth term
[tex]a_{n}[/tex] = a₁ [tex](r)^{n-1}[/tex]
where a₁ is the first term and r the common ratio
Here a₁ = 3 and r = 5 , then
[tex]a_{n}[/tex] = 3 [tex](5)^{n-1}[/tex]
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