Answered

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ILL GIVE BRAINLIEST
find the value of the constant a for which there is no term in x² of the expansion of (1+ax) (2+3x)³

Sagot :

maniknandini

Answer:

a = -3/2 = -1.5

Step-by-step explanation:

(1+ax) (2+3x)³

Formula

(a+b)^3=a^3+3a^2b+3ab^2+b^3

(1 + ax) [ 2^3 + 3*2^2*3x + 3*2*(3x)^2 + (3x)^3]

(1 + ax) [ 8 + 12*3x + 6*9x^2 + 27x^3]

8 + 12*3x + 6*9x^2 + 27x^3 + 8ax + 36ax^2 + 54ax^3 + 27ax^4

coefficient of x^2 is zero

54x^2 + 36ax^2

54 + 36a = 0

36a = -54

a = -3/2

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